Find the equation of the tangent to the curve at x = 3 for the parametric equations:
Find the equation of the tangent to the curve at x = 3 for the parametric equations: x=t+(1/t) y=t^2 +(1/t^2), with t > 0For what value of t is the slope of the curve undefined for the graph defined by x = 8 – t3, y = t2– 6t?
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what is the Cartesian equation for the parametric equationx= square root of t, y = 2t + 5?
Findd^2y/dx^2for the curve given by x = t2and y = t3.
what is the slope of the tangent to the curve with parametric equations x = t5– 4t3, y = t2, at t = 2?,
11x=t+ ; y =t 2 + 2tt This curve can be written implicitly asAt ( 3,7 ) the tangent has slope Hence the equation of tangent at 3 (parabola) dy=6dxx=3 is given as y−7=6 ( x−3 ) 2 x=8 –…
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